GAME01
1/2 |
Left |
Middle |
Right |
UP |
(1,0) |
(1,2) |
(0,1) |
DOWN |
(0,3) |
(0,1) |
(2,0) |
- 双行列ゲーム (bimatrix game)
- For 1
- if 2 choose L,U is bette than D.
- if M,U is bette than D.
- if R,however,D is bette.
- For 2
- if 1 choose U,M>R>L
- if D,L>M>R
- For 1,neither of two is strictly dominated.
- For 2,R is strictly dominated by M
- If 1 know about that and 2 is rational player,we can think case01 like case02
1/2 |
left |
Middle |
UP |
(1,0) |
(1,2) |
DOWN |
(0,3) |
(0,1) |
In this case,
- For 1
- if 2 choose L,U is bette than D.
- if M,U is bette than D.
- For 2
- if 1 choose U,M>L
- if D,L>M
- For 2,neither of two is strictly dominated.
- For 1,D is strictly dominated by U.
- If 2 know that 1 know that 2 is rational,then 2 eliminate D,like case 03
1/2 |
left |
Middle |
UP |
(1,0) |
(1,2) |
So,(U,M)is the outcome of this game.
GAME02
1/2 |
L |
C |
R |
T |
0,4 |
4,0 |
5,3 |
M |
4,0 |
0,4 |
5,3 |
B |
3,5 |
3,5 |
6,6 |
- for 1
- if 2 were to play L,M>B>T
- if C,T>B>M
- if R,B>T=M
- For 2
- if 1 were to play T,L>R>C
- if M,C>R>L
- if B,R>L=C
- Thus,there is no strictly D strategies..
- Next,we think best response to the each strategies,
- for 1
- if 2 were to play L,M is the best.
- if C,T.
- if R,B.
- For 2
- if 1 were to play T,L is the best.
- if M,C.
- if B,R.
- In that process, we can see (B,R) as a only strategy pair that satisfies (NE).
参考
Robert Gibbons [1992]:『Game Theory for applied economists』
最終更新:2010年08月01日 01:19